How to get entry ID from current user? « Gravity Support Forums

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Tobe
Member

I have a form for users only, and made sure users can only submit the form only once.
Once the form is submitted, a page is created using the entry ID as part of the title and url.

How can I :
1- Auto check if the user have already submitted the form, and if so;
2- Hide the form and instead get the user's entry ID and add that to a url ( example.com/number-{entry-id} ) or else;
3- Display the form.

Thanks in advance!

Posted 12 years ago on Wednesday April 17, 2013 | Permalink
Tobe
Member

I tried a lot using the is_user_logged_in function, but that only gives a blank screen.....(no error, no styling, just blank screen on all pages) But if I find a solution for that, how do I make my website check the e-mail address of that user and compare it with all the form entries to find a match, and then get the info from thet form entry to use in a text maybe using merge tags?

Or is it impossible to display some of the user's entries of a form with some additional text instead of the form itself once the user have submitted the form?
(Or maybe to create a shortcode for that?)

Who is keen enough to find a solution?
I would appreciate your input a lot ;-)

Posted 11 years ago on Thursday April 18, 2013 | Permalink

Tobe
Member

This is what I got so far.

Function to make form-ID=2 to create a page instead of post (thanks to Chris):

add_filter("gform_post_data", "change_post_type", 10, 2);
function change_post_type($post_data, $form){
    //only change post type on form id 1
    if($form["id"] != 2)
       return $post_data;

    $post_data["post_type"] = "page";
    return $post_data;
}

Code in my page.php to determine what to display depending if user is signed in (or not) and if user do have a page created or not:

<?php if ( is_user_logged_in() ) { ?>

<?php global $wpdb;
$user = wp_get_current_user();
$where = get_posts_by_author_sql( 'page', true, $user->ID );
$count = $wpdb->get_var( "SELECT COUNT(*) FROM $wpdb->posts $where" );

if ( $count >= 1 ) { ?>
// This is what user see if form is submitted, where '{entry-ID}' should be replaced by the user's entry iD
<h2>Hey <?php echo $current_user->display_name ?>, thank you for submitting the form. Visit your page here: http://www.example.com/{entry-ID}</h2>

<?php } else { ?>
// If user have not submitted a form, user is shown the info below with the form to submit
<h2>Hey <?php echo $current_user->display_name ?>, Thank you for joining. To create a page please submit the form below:</h2><?php echo do_shortcode('[gravityform id="2" name="Join the movement of Gooders" title="false" description="false"]'); ?>

<?php } } else { ?>
// if user is not logged in, user is urged to log in to submit form
<h2><Please log in to create a page <?php do_action( 'wordpress_social_login' ); ?></h2>

<?php } ?>

Question that is left now:
What code/function should I use to display the user's entry ID (on form 2) into the url on the second option like: http://www.example.com/{entry-ID} ??

Posted 11 years ago on Saturday April 20, 2013 | Permalink