Is it possible to identify which page the form was launched from?
<a href="http://www.domain.com/form-page" class="colorboxiframe">Form Page</a>
The form shortcode is on a Wordpress Page called "form-page".
The form is loaded with an iframe using colorbox.
The above code is inserted automatically to a number of pages. I need to know when the user fills out the form where they came from...
any other ideas on how to achieve the same thing?
So, you are calling the form page from multiple pages, and the "embed URL" will not work because it would always be "form-page"? Normally, the embed URL is the page the form is launched from. That is true even in your case, but that is not the URL you want.
The code is inserted automatically into multiple pages ... so you can't edit the shortcode? Can you explain how the shortcode is included in multiple pages automatically? I think you will need to have a hidden field in the form which is embedded in 'form-page' and include that field in the query string. Or, you can include a value in the short code:
[gravityforms id=1 field_values='page_url=Page Title Here']That would populate a hidden field in your form with a parameter name of "page_url".
Any thoughts?
Yes that looks like what I want but not sure how to pass that value using an iframe... i think it's impossible so i will need to revise my process..
To make things clearer
1. A file called single-footer.php is loaded onto multiple pages.
2. The file single-footer.php contains the launch code for the form which is:
<a href="http://www.domain.com/form-page" class="colorboxiframe">Form Page</a>
3. The class 'colorboxiframe' makes the form load into a popup iframe.
Problem, how to pass the name of the page it was launched from to the hidden field. Presumably the necessary code needs to go to single-footer.php
What if you captured the post ID in your single-footer.php, like this:
[php]
global $post;
$thisid = $post->ID;Then, in the shortcode or function (your launch code) where you include the form, pre-populate the page ID in a hidden field. Would that work for you?
I just tried it here:
http://gravity.chrishajer.com/2012/08/22/map-to-fun/
I added this code to my footer.php:
[php]
<?php
global $post;
$thisid = $post->ID;
echo "<!-- You are on page " . site_url() . "/?p=" . $thisid . " -->";
?>If you look in the source of that page, you will see the HTML comment:
[html]
<!-- You are on page http:// gravity. chrishajer. com/?p=870 -->This code will work fine on a single page (like where your single-footer.php is likely in use.) It would not return the correct value when used on an index page or archive page, due to the loop.
Based on your latest response, which was posted after my response, I think in your footer, where the link to the form is, you need to send a query string like this:
http://www.domain.com/form-page/?frompage=$postid
Where $postid is from my previous code. Then in form 10, you need to have a hidden field called "Source Page" or "Referring Page" or something, check the box on the advanced tab to "Allow Field to be Populated Dynamically" and enter a parameter name of frompage since that is what we are sending over from the single-footer.php.
Can you put all those pieces together?
ok, it's rather hard for me to work out.. i can't even get
echo "<!-- You are on page " . site_url() . "/?p=" . $thisid . " -->";
to show on the page, these are custom post types too.. would it be possible to send you my login details to test?
update... i figured it out! but i used a hard-coded name :)
http://www.domain.com/form-page?frompage=hard-coded
so the only problem is to figure out each posts title which i thought would be the easier part using the code:
<?php
global $post;
$thisid = $post->ID;
echo "<!-- You are on page " . site_url() . "/?p=" . $thisid . " -->";
?>Right on - glad you got it sorted out.
